### Not so Mobile

#### Problem Description

Before being an ubiquous communications gadget, a *mobile* was just a structure made of strings and wires suspending colourfull things. This kind of mobile is usually found hanging over cradles of small babies.

The figure illustrates a simple mobile. It is just a wire, suspended by a string, with an object on each side. It can also be seen as a kind of lever with the fulcrum on the point where the string ties the wire. From the lever principle we know that to balance a simple mobile the product of the weight of the objects by their distance to the fulcrum must be equal. That is *W*_{l}×*D*_{l} = *W*_{r}×*D*_{r} where *D*_{l} is the left distance, *D*_{r} is the right distance, *W*_{l} is the left weight and *W*_{r} is the right weight.

In a more complex mobile the object may be replaced by a sub-mobile, as shown in the next figure. In this case it is not so straightforward to check if the mobile is balanced so we need you to write a program that, given a description of a mobile as input, checks whether the mobile is in equilibrium or not.

#### Input

**The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.**

The input is composed of several lines, each containing 4 integers separated by a single space. The 4 integers represent the distances of each object to the fulcrum and their weights, in the format: *W*_{l} *D*_{l} *W*_{r} *D*_{r}

If *W*_{l} or *W*_{r} is zero then there is a sub-mobile hanging from that end and the following lines define the the sub-mobile. In this case we compute the weight of the sub-mobile as the sum of weights of all its objects, disregarding the weight of the wires and strings. If both *W*_{l} and *W*_{r} are zero then the following lines define two sub-mobiles: first the left then the right one.

#### Output

**For each test case, the output must follow the description below. **Write `YES\' if the mobile is in equilibrium, write `NO\' otherwise.

#### Sample Input

1 0 2 0 4 0 3 0 1 1 1 1 1 2 4 4 2 1 6 3 2

#### Sample Output

YES